Question 31 (1 point) PRC4A17-A1-8 -3-7 A uniform bar 1.1 metres in length and having a cross sectional area of 11.5cm^2 is subject to a loading of 9000 Newtons Calculate the stress produced in kPa. square A I

Here's how to calculate the stress:<br /><br />1. **Convert the area to square meters:**<br /> 11.5 cm² * (1 m / 100 cm)² = 0.00115 m²<br /><br />2. **Calculate the stress:**<br /> Stress = Force / Area<br /> Stress = 9000 N / 0.00115 m² <br /> Stress = 7,826,086.96 Pa<br /><br />3. **Convert to kPa:**<br /> Stress = 7,826,086.96 Pa * (1 kPa / 1000 Pa)<br /> Stress ≈ 7826.1 kPa<br /><br />Therefore, the stress produced is approximately **7826.1 kPa**.<br />