Find the force in newtons needed to slow a 2500 kg truck from 20m/s to 10m/s in 100m. Hint:keep in mind the truck is slowing down.

Here's how to find the force needed to slow the truck:<br /><br />1. **Calculate the change in velocity (Δv):**<br /><br /> Δv = Final velocity - Initial velocity <br /> Δv = 10 m/s - 20 m/s = -10 m/s (The negative sign indicates deceleration)<br /><br />2. **Calculate the acceleration (a):** We can use the following equation of motion:<br /><br /> v² = u² + 2as<br /><br /> Where:<br /> * v = final velocity (10 m/s)<br /> * u = initial velocity (20 m/s)<br /> * a = acceleration (what we want to find)<br /> * s = distance (100 m)<br /><br /> Rearranging the equation to solve for 'a':<br /><br /> a = (v² - u²) / 2s<br /> a = (10² - 20²) / (2 * 100)<br /> a = (100 - 400) / 200<br /> a = -300 / 200<br /> a = -1.5 m/s² (Again, the negative sign indicates deceleration)<br /><br />3. **Calculate the force (F):** Use Newton's second law of motion:<br /><br /> F = ma<br /><br /> Where:<br /> * F = force (what we want to find)<br /> * m = mass (2500 kg)<br /> * a = acceleration (-1.5 m/s²)<br /><br /> F = 2500 kg * (-1.5 m/s²)<br /> F = -3750 N<br /><br />Therefore, the force needed to slow the truck is 3750 N. The negative sign indicates that the force is acting opposite to the direction of motion (i.e., it's a braking force).<br />